Written by Allen Wyatt (last updated December 2, 2023)
This tip applies to Excel 2007, 2010, 2013, 2016, 2019, 2021, and Excel in Microsoft 365
William is trying to find the median of about 3,000 numbers in a column that has a range from 0.9 to 5. However, he only wants the median of numbers that are greater than 1. He can't figure out how to put that parameter into his formula and is looking for ideas.
Short of creating a user-defined function in a macro, there are a couple of ways you can go about determining the median. One method is to use an intermediate column that contains only those values above 1 and then calculate the median based on those values. You could also use an advanced filter to extract only the values above 1 and then use those values to find the median.
A better approach, however, is to use a simple array formula:
=MEDIAN(IF($A$1:$A$3000>1,A1:A3000))
In earlier versions of Excel you'll need to enter this as an array formula by using Ctrl+Shift+Enter. (In Microsoft 365 or Excel 2021 you can just press Enter.) The result is your median value, with your criteria taken into account.
ExcelTips is your source for cost-effective Microsoft Excel training. This tip (7922) applies to Microsoft Excel 2007, 2010, 2013, 2016, 2019, 2021, and Excel in Microsoft 365. You can find a version of this tip for the older menu interface of Excel here: Median of Selected Numbers.
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2023-12-03 10:57:08
J. Woolley
The Tip's formula works because MEDIAN ignores text, logical values, or empty cells in an array or reference argument; therefore, FALSE values in the formula's array argument are not interpreted as zero values. Notice this formula would produce a different result because FALSE is replaced by zero:
=MEDIAN(IF($A$1:$A$3000>1,A1:A3000,0))
(It should also be noted that logical values and text representations of numbers typed directly into MEDIAN's list of arguments are NOT ignored.)
The Tip says, "In earlier versions of Excel you'll need to enter this as an array formula by using Ctrl+Shift+Enter." I don't think this is necessary because the formula does not return an array.
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