**Please Note: **
This article is written for users of the following Microsoft Excel versions: 2007, 2010, 2013, 2016, 2019, and Excel in Microsoft 365. If you are using an earlier version (Excel 2003 or earlier), *this tip may not work for you*. For a version of this tip written specifically for earlier versions of Excel, click here: Splitting Cells by Case.

Written by Allen Wyatt (last updated March 13, 2021)**This tip applies to** Excel 2007, 2010, 2013, 2016, 2019, and Excel in Microsoft 365

Manik has a worksheet that, in column A, has text values in the format "mikeDAVIS", where the person's first name is in lowercase and the last name is in uppercase. He would like to split the names to two separate columns, according to the case of the text.

This can be accomplished using either a formula or a macro. Regardless of which approach you use, the key is to figure out where the text switches from lower- to uppercase. This can only be done by examining each character in the string. So, if you want to use a formulaic approach, then you'll need to use an array formula. The following array formula returns the last name of whatever is in cell A1:

=MID(A1,MATCH(1,(CODE(MID(A1,ROW($1:$255),1))>=65) *(CODE(MID(A1,ROW($2:$255),1))<90),)+1,255)

Remember, since this is an array formula, you should enter it by pressing **Ctrl+Shift+Enter**. It returns everything in the cell starting with the first uppercase letter it finds. Thus, in "mikeDAVIS" it would return "DAVIS" and in "mikeDavis" it would return "Davis". Assuming that you use the array formula in cell B1, you could then determine the first name by using the following:

=SUBSTITUTE(A1,B1,"")

This is a regular formula, not an array formula.

There are many similar array formulas that can accomplish much the same task. For example, this array formula will return the first name (all the characters up to the first uppercase character) of whatever is in cell A1:

=LEFT(A1,MAX((CODE(MID(A$1,ROW(INDIRECT("1:"& LEN(A1))),1))>96)*ROW(INDIRECT("1:"&LEN(A1)))))

You can then use the same regular formula (the one that uses the SUBSTITUTE function) to derive the last name.

If you want to use a macro approach to finding the names, all you need to do is come up with a formula that will return the location of the first capital letter in the text. The following code returns this "change point" in the text:

Function GetFirstUpper(MyCell As Range) As Integer Dim sCellValue As String Dim i As Integer sCellValue = Trim(MyCell.Value) i = 1 Do While (Asc(Mid(sCellValue, i, 1)) > 90 _ Or Asc(Mid(sCellValue, i, 1)) < 65) _ And i < Len(sCellValue) + 1 i = i + 1 Loop If i > Len(sCellValue) Then GetFirstUpper = 99 Else GetFirstUpper = i End If End Function

To use the function, let's assume that the name is in cell A1. You could find the first and last names using these formulas in your worksheet:

=LEFT(A1,GetFirstUpper(A1)-1) =MID(A1,GetFirstUpper(A1),LEN(TRIM(A1))-GetFirstUpper(A1)+1)

If you prefer your macro to return the actual names, you could use the following one to return everything before the first capital letter:

Function GetFirstName(MyCell As Range) As String Dim sCellValue As String Dim i As Integer sCellValue = Trim(MyCell.Value) i = 1 Do While (Asc(Mid(sCellValue, i, 1)) > 90 _ Or Asc(Mid(sCellValue, i, 1)) < 65) _ And i < Len(sCellValue) + 1 i = i + 1 Loop If i > Len(sCellValue) Then GetFirstName = sCellValue Else GetFirstName = Left(sCellValue, i - 1) End If End Function

To use the macro, all you need to do is use the following in a worksheet cell. (This assumes that the text string to be evaluated is in cell A1.)

=GetFirstName(A1)

A minor variation on the macro will allow you to similarly fetch the last name, which is assumed to be everything starting with the first capital letter encountered.

Function GetLastName(MyCell As Range) As String Dim sCellValue As String Dim i As Integer sCellValue = Trim(MyCell.Value) i = 1 Do While (Asc(Mid(sCellValue, i, 1)) > 90 _ Or Asc(Mid(sCellValue, i, 1)) < 65) _ And i < Len(sCellValue) + 1 i = i + 1 Loop If i > Len(sCellValue) Then GetLastName = sCellValue Else GetLastName = Mid(sCellValue, i) End If End Function

If you prefer, you could combine the macros into a single function that would, based upon what you specify, return either the first or last name:

Function GetName(MyCell As Range, sWanted As String) As String Dim sCellValue As String Dim i As Integer sCellValue = Trim(MyCell.Value) i = 1 Do While (Asc(Mid(sCellValue, i, 1)) > 90 _ Or Asc(Mid(sCellValue, i, 1)) < 65) _ And i < Len(sCellValue) + 1 i = i + 1 Loop If i > Len(sCellValue) Then GetName = sCellValue Else If LCase(sWanted) = "first" Then GetName = Left(sCellValue, i - 1) Else GetName = Mid(sCellValue, i) End If End If End Function

To use this combined function, you simply need to specify which name you want:

=GetName(A1, "First")

The word "First" passed as a parameter in this manner returns the first name (everything before the first capital letter). Any other string passed as the second parameter (such as "Last" or "xxx" or "Rest" or even "") results in the last name being returned.

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This tip (9091) applies to Microsoft Excel 2007, 2010, 2013, 2016, 2019, and Excel in Microsoft 365. You can find a version of this tip for the older menu interface of Excel here: **Splitting Cells by Case**.

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2021-03-15 09:44:39

Willy Vanhaelen

Your solution of inserting a character 1 at the position before the first upper case letter and then splitting the string into an array is high-tech vba: “chapeau”. This solved the “mary ann” case.

But at the request of Dean Parker in the pre 2007 version of this tip I made my GetName function so it could handle “MIKEdavis” as well as “mike DAVIS”. Your function doesn’t deal with that.

So, I changed your function a bit and I think we now get the best of both worlds:

mary annSMITH as well as MARY ANNsmith:

Function GetName(S As String, Optional First As Boolean = True) As String

Dim X As Long

For X = 1 To Len(S)

If Mid(S, X, 1) Like IIf(Asc(S) > 90, "[A-Z]", "[a-z]") Then Exit For

Next

GetName = Split(Application.Replace(S, X, 0, Chr(1)), Chr(1))(1 + First)

End Function

As for your second point, this is the result of the fact that my original function handles both mikeDAVIS and MIKEdavis. With argument 1 the first part of the text can be either lower or upper case depending on the case of the text’s first letter. So, with only upper-case text the function with no argument will return an empty string because there is no lower-case text to display.

2021-03-14 07:25:56

Peter Atherton

Mary Ann LIGHTLY could be entered with a hard (non breaking) space. e.g.Mary Alt & 0160 & Ann " " LIGHTLY

Hear are my solutions, the secondwith a little bit of checking.

Function FName(s As String, Optional delimiter = " ")

Dim x

x = Split(s, delimiter)

FName = x(0)

End Function

Function LName(s As String, Optional delimiter = " ")

Dim x

x = Split(s, delimiter)

LName = x(1)

End Function

Function FName2(s As String, Optional delimiter = " ")

Dim x, i As Long, str As String, c As String

x = Split(s, delimiter)

For i = LBound(x) To LBound(x)

c = Mid(x(i), 2, 1)

If c = LCase(c) Then

FName2 = x(0)

End If

Next

End Function

Function LName2(s As String, Optional delimiter = " ")

Dim x, i As Long, str As String, c As String

x = Split(s, delimiter)

LName2 = x(UBound(x))

End Function

2021-03-13 16:22:13

Rick Rothstein

Two things about your GetName function...

1) I have a friend whose first name contains a space in it (Mary Ann where Ann is not a middle name). If we assume the space will be retained as part of the lower case text, your function mishandles it.

2) If the text in the cell is all upper case letters or all lower case letters (think the name Cher), then your GetName function returns the text for either condition if the second argument is 1 and returns the empty text string ("") if the second argument is anything other than 1.

2021-03-13 15:58:51

Rick Rothstein

Function GetFirstName(S As String) As String

Dim X As Long

For X = 1 To Len(S)

If Mid(S, X, 1) Like "[A-Z]" Then Exit For

Next

GetFirstName = Left(S, X - 1)

End Function

Function GetLastName(S As String) As String

Dim X As Long

For X = 1 To Len(S)

If Mid(S, X, 1) Like "[A-Z]" Then Exit For

Next

GetLastName = Mid(S, X)

End Function

Function GetName(S As String, Optional First As Boolean = True) As String

Dim X As Long

For X = 1 To Len(S)

If Mid(S, X, 1) Like "[A-Z]" Then Exit For

Next

GetName = Split(Application.Replace(S, X, 0, Chr(1)), Chr(1))(1 + First)

End Function

2021-03-13 10:02:53

Willy Vanhaelen

Here are my tiny versions who do the job more efficiently of course and without errors:

Function GetFirstUpper(myCell As Range) As Integer

Dim S As String, X As Integer

For X = 1 To Len(myCell)

S = Mid(myCell, X, 1)

If S = UCase(S) Then Exit For

Next X

GetFirstUpper = X

End Function

'---

Function GetFirstName(myCell As Range) As String

GetFirstName = Left(myCell, GetFirstUpper(myCell) - 1)

End Function

'---

Function GetLastName(myCell As Range) As String

GetLastName = Mid(myCell, GetFirstUpper(myCell))

End Function

My version of the combined macro does the split when the case changes. So it works as well with firstLAST as with FIRSTlast:

Function GetName(MyCell As Range, Optional sWanted As Integer) As String

Dim S As String, X As Integer

For X = 1 To Len(MyCell)

S = Mid(MyCell, X, 1)

If S = IIf(Asc(MyCell) > 90, UCase(S), LCase(S)) Then Exit For

Next X

GetName = IIf(sWanted = 1, Left(MyCell, X - 1), Mid(MyCell, X))

End Function

To use this function to get the first part you have to enter: =GetName(A1,1) instead of =GetName(A1, "First").

Any other number for the second argument or if you omit it will yield the last part.

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