Christine needs a way to calculate the first Tuesday of any given month. So, given a month and a year, she needs to get the date of that first Tuesday.

There are quite a few different formulas you can use to achieve the desired result. Most approaches use the WEEKDAY function in some way because it can return a numeric value representing the day of the week for any given date. Assuming that you put a month in cell A1 (1 through 12) and a four-digit year in cell A2, then the following formulas will all return a date for the first Tuesday in the month. (I've arranged the formulas in order of length, from longest to shortest.)

=DATE(A2,A1,1)+IF(WEEKDAY(DATE(A2,A1,1))=3,0,IF(WEEKDAY(DATE(A2,A1,1))>3,7-WEEKDAY(DATE(A2,A1,1))+3,3-WEEKDAY(DATE(A2,A1,1)))) =IF(3-WEEKDAY(DATE(A2,A1,1))>=0,DATE(A2,A1,1)+3-WEEKDAY(DATE(A2,A1,1)),DATE(A2,A1,1)+7+3-WEEKDAY(DATE(A2,A1,1))) =DATE(A2,A1,1)+IF(3-WEEKDAY(DATE(A2,A1,1))>=0,3-WEEKDAY(DATE(A2,A1,1)),10-WEEKDAY(DATE(A2,A1,1))) =DATE(A2,A1,1)-WEEKDAY(DATE(A2,A1,1),1)+3+IF(WEEKDAY(DATE(A2,A1,1),1)>3,7,0) =DATE(A2,A1,1)+8-DAY(DATE(A2,A1,1))-WEEKDAY(DATE(A2,A1,1)-DAY(DATE(A2,A1,1))-2) =DATE(A2,A1,1)+3-WEEKDAY(DATE(A2,A1,1))+(1-(3>=WEEKDAY(DATE(A2,A1,1))))*7 =DATEVALUE(A2&"/"&A1&"/1")+MOD(10-WEEKDAY(DATEVALUE(A2&"/"&A1&"/1")),7) =DATE(A2,A1,MATCH(TRUE,WEEKDAY(DATE(A2,A1,{1,2,3,4,5,6,7}))=3,0)) =DATE(A2,A1,MOD(10-WEEKDAY(DATE(A2,A1,1)),7)+1) =DATE(A2,A1,1)+MOD(3-WEEKDAY(DATE(A2,A1,1)),7) =DATE(A2,A1,1)+7-WEEKDAY(DATE(A2,A1,1),13) =DATE(A2,A1,8-WEEKDAY(DATE(A2,A1,1),13)) =DATE(A2,A1,7)-MOD(DATE(A2,A1,7)-3,7) =DATE(A2,A1,8-WEEKDAY(DATE(A2,A1,5))) =DATE(A2,A1,8)-WEEKDAY(DATE(A2,A1,5))

If you find it more convenient to specify a date within the month you want to evaluate, then you can modify the formulas to take that into account. The follow are just a few formulas you could use if you put an actual date into cell A1:

=DATE(YEAR(A1),MONTH(A1),MATCH(TRUE,WEEKDAY(DATE(YEAR(A1),MONTH(A1),{1,2,3,4,5,6,7}))=3,0)) =DATE(YEAR(A1),MONTH(A1),MOD(10-WEEKDAY(DATE(YEAR(A1),MONTH(A1),1)),7)+1) =DATE(YEAR(A1),MONTH(A1),1)+MOD(3-WEEKDAY(DATE(YEAR(A1),MONTH(A1),1)),7) =DATE(YEAR(A1),MONTH(A1),1)+7-WEEKDAY(DATE(YEAR(A1),MONTH(A1),1),13) =DATE(YEAR(A1),MONTH(A1),8-WEEKDAY(DATE(YEAR(A1),MONTH(A1),1),13)) =DATE(YEAR(A1),MONTH(A1),7)-MOD(DATE(YEAR(A1),MONTH(A1),7)-3,7) =DATE(YEAR(A1),MONTH(A1),8-WEEKDAY(DATE(YEAR(A1),MONTH(A1),5))) =DATE(YEAR(A1),MONTH(A1),8)-WEEKDAY(DATE(YEAR(A1),MONTH(A1),5)) =A1-DAY(A1)+7-WEEKDAY(A1-DAY(A1)-1,3)

Finally, you may want to consider a macro-based approach. The following is a user-defined function that quickly figures out the first Tuesday:

Function FirstTuesday(M As Integer, Y As Integer) As Date Dim dResult As Date dResult = DateSerial(Y, M, 1) Do While Weekday(dResult) <> vbTuesday dResult = DateAdd("d", 1, dResult) Loop FirstTuesday = dResult End Function

All you need to do in your worksheet is to pass the user-defined function the numeric month and year desired:

=FirstTuesday(6,2018)

If you prefer, you can specify that the month and year are in a cell:

=FirstTuesday(A2,A1)

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2018-06-25 10:15:43

Willy Vanhaelen

I think it's an execellent idea. It makes the formula easier to use. And it appropriate you can still use ± n days.

2018-06-25 09:43:12

Peter Atherton

Willy

Thanks for the new function and yes it is easier to understand. I will view Nick Rothstein and your comments after posting this.

I took the liberty of adding another variable to the Firstday function that I think makes it less likely to enter an error. What do you think?

Function FirstDay(Y As Integer, M As Integer, D As Integer, _

Optional wk2Add As Integer = 0) As Date

'Willy Vanhaelen

FirstDay = Application.Floor(DateSerial(Y, M, 7 - D), 7) + D + 7 * wk2Add

End Function

(see Figure 1 below)

**Figure 1.**

2018-06-24 12:58:55

Willy Vanhaelen

Thanks for the compliment. While trying to answer your question I did some testing and realised that in this case the Evaluate method is not the best choice.

The result is an even shorter version of the UDF (and easier to understand):

Function FirstDay(Y As Integer, M As Integer, D As Integer) As Date

FirstDay = Application.Floor(DateSerial(Y, M, 7 - D), 7) + D

End Function

The Evaluate method is a good choice though to implement Excel's array formulas in VBA to avoid the use of a Loop resulting in much faster macros. If you are interested you can read the comments of Rick Rothstein and myself in this tip:

https://excelribbon.tips.net/T010768_Shortening_ZIP_Codes.html

It's a fact that that the Evaluate method is the most poorly commented item in Excel's Help. If you want more, simple Google for "vba evaluate".

BTW: there is an error in row 4 of my picture: Third Tuesday of July should be Fourth Tuesday (or +21 in the formula must by +14 to get the third).

2018-06-24 05:14:38

Peter Atherton

Excellent stuff as usual! The UDF is definitely one for the Personal workbook.

Can you point me to to a good write-up on the Evaluate function? Thanks.

2018-06-23 06:41:50

Willy Vanhaelen

Here is a one-liner User Defined Function that does it all:

Function FirstDay(Y As Integer, M As Integer, D As Integer) As Date

FirstDay = Evaluate("FLOOR(DATE(" & Y & "," & M & "," & 7 - D & "),7)+" & D)

End Function

Syntax: =FirstDay(year,month,weekday)

weekday: 1 for Sunday ... 7 for Saturday

If you need to use this often then place the macro in a module of your Personal workbook and it will be available in any workbook you open.

Here are some examples:

(see Figure 1 below)

**Figure 1.**

2018-06-20 14:38:58

Willy Vanhaelen

@Peter Atherton

Here is a much shorter formula to do the job:

=FLOOR(DATE(B2,B1,7-B4),7)+B4

(see Figure 1 below)

**Figure 1.**

2018-06-20 09:19:40

Peter Atherton

Ignore the last post.

The following returns the first date for any workday.

=DATE(B2,B1,1)+ABS(7-WEEKDAY(DATE(B2,B1,1)+7-B4))

(see Figure 1 below)

**Figure 1.**

2018-06-19 06:31:05

Peter Atherton

Willy

a variation on your smashing formula

=CEILING(DATE($B$2,$B$1,1+Rwkday),7)-(1+Rwkday) to find th first occurrunce

and

=(CEILING(DATE($B$2,$B$1,1+Rwkday),7)-(1+Rwkday)+7*(WkNumber-1)) to get the nth occurence

(see Figure 1 below)

**Figure 1.**

2018-06-17 08:08:38

Willy Vanhaelen

If you use my formula you get the same result:

=CEILING(DATE(B2,B1,5),7)-4

but it is half the size :-).

2018-06-16 21:59:51

Erik

For example:

• input your month (1-12) in cell B1

• input the four-digit year in cell B2

• use this formula: =DATE(B2,B1,1)+7-WEEKDAY(DATE(B2,B1,1),13)

Be sure the formula cell is formatted as a date so the result is legible.

2018-06-16 08:28:37

Willy Vanhaelen

=CEILING(DATE(A2,A1,5),7)-4

As for the macro, here is a one-liner:

Function FirstTuesday(M As Integer, Y As Integer) As Date

FirstTuesday = Evaluate("CEILING(DATE(" & Y & " ," & M & ",5),7)-4")

End Function

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