Extracting Numbers from a Text String

Written by Allen Wyatt (last updated April 25, 2026)
This tip applies to Excel 2007, 2010, 2013, 2016, 2019, 2021, 2024, and Excel in Microsoft 365


2

Bob inherited a workbook that includes several hundred text values in column C. Many of these include, within the text, a number that is surrounded by parentheses, such as "Falcon (123) Vector". Bob needs to extract those numbers. The number can have different numbers of digits, it can be in different places in the text, and not all cells may include a number or parentheses. Bob wonders if this can be done with a formula, or if a macro would work best.

This can be done with a formula, but the formula you choose will need to depend on the characteristics of the data in column C. Assuming your data begins in cell C2, a simple approach is to use the TEXTBEFORE and TEXTAFTER functions, available in Excel 2024 and Microsoft 365:

=TEXTBEFORE(TEXTAFTER(C2,"("),")")

This returns a text string composed of the numbers within the parentheses. If you want it to be a numeric value instead, then you can wrap it in a VALUE function:

=VALUE(TEXTBEFORE(TEXTAFTER(C2,"("),")"))

The value of this approach diminishes if your data includes cells that either contain no parentheses; just an opening or closing parenthesis; or that do contain parentheses, but no numbers between those parentheses. In that case, you may want to wrap the formula in an IFERROR function:

=IFERROR(VALUE(TEXTBEFORE(TEXTAFTER(C2,"("),")")),"")

This results in the numeric value being returned unless one of the conditions already described occurs, in which case an empty string ("") is returned. If you prefer that something else be returned, such as the text "no number," then you can place the desired text within the final empty string ("").

If you are using Microsoft 365, you might think that the best approach is to use the new REGEXTRACT or REGEXREPLACE functions, in this manner:

=IFERROR(VALUE(REGEXEXTRACT(C2,"\d+")),"")
=IFERROR(VALUE(REGEXREPLACE(C2,"\D+","")),"")

These work just as well as the TEXTBEFORE and TEXTAFTER approach, with a couple of exceptions. First, they mess up if there is a missing beginning or ending parenthesis. (For instance, "Falcon (123 Vector" or "Falcon 123) Vector" still return the value 123 but shouldn't.) A better REGEXTRACT approach that even spills for the full length of column C is this:

=IFNA(REGEXEXTRACT(C.:.C, "\((\d+)\)", 2), "")

None of the REGEX approaches work as well as the TEXTBEFORE and TEXTAFTER approach if your cells contain negative numbers within the parentheses or if there is an exponent (such as "Falcon (7E2) Vector").

If you are using an older version of Excel, then you can rely on the FIND function. Even though the formula is a bit longer, it works essentially the same as using TEXTBEFORE and TEXTAFTER:

=IFERROR(VALUE(MID(C2,FIND("(",C2)+1,FIND(")",C2)-FIND("(",C2)-1)),"")

If you want to forego formulas all together and your data is rather simple in nature, you can rely on Flash Fill. In the cell to the right of your first value, type the correct result. Thus, if cell C2 contains "Falcon (123) Vector", you would type "123" in cell D2. Select cell D2, and then press Ctrl+E. Excel fills every cell in column D with the number extracted from the text in column C.

Notice I said that your data needs to be rather simple. The Flash Fill approach doesn't work well if your data has cells that don't include parentheses, don't have an opening or closing parenthesis, or have parentheses that contain letters instead of numbers. In that case, you are better off with picking a formulaic approach that best matches the nature of your data.

Also, Flash Fill may not be the way to go if your data in column C changes. It produces static results, and if your source data changes, you will need to delete the contents of column D and again use the Flash Fill steps to generate new results.

If you prefer to go the route of a macro, then the following creates a user-defined function that you can use:

Function ParenNum(sTarget As Range)
    Dim sRaw As String
    Dim iStart As Integer
    Dim iEnd As Integer
    Dim J As Integer
    Dim sNum As String
    Dim bValid As Boolean

    ParenNum = ""
    If sTarget.Cells.Count = 1 Then
        sRaw = sTarget.Text
        iStart = InStr(1, sRaw, "(", vbTextCompare)
        If iStart > 0 Then
            iEnd = InStr(iStart, sRaw, ")", vbTextCompare)
            If iEnd > 0 Then
                sNum = Mid(sRaw, iStart + 1, iEnd - iStart - 1)
                If Len(sNum) > 0 Then
                    bValid = True
                    For J = 1 To Len(sNum)
                        If Asc(Mid(sNum, J, 1)) < 48 _
                          Or Asc(Mid(sNum, J, 1)) > 58 Then
                            bValid = False
                            Exit For
                        End If
                    Next J
                    If bValid Then ParenNum = CLng(sNum)
                End If
            End If
        End If
    End If
End Function

To use the function, simply reference the cell to be used in the extraction in this manner:

=ParenNum(C2)

The ParenNum user-defined function is very strict about what can be between the parentheses. If there is a negative sign or an E (for an exponent), then the function treats those characters as text and, therefore, returns an empty string. If you want the function to accept negatives or exponents, then the following variation should work just fine:

Function ParenNum2(sTarget As Range)
    Dim sRaw As String
    Dim iStart As Integer
    Dim iEnd As Integer
    Dim J As Integer
    Dim sNum As String

    ParenNum = ""
    If sTarget.Cells.Count = 1 Then
        sRaw = sTarget.Text
        iStart = InStr(1, sRaw, "(", vbTextCompare)
        If iStart > 0 Then
            iEnd = InStr(iStart, sRaw, ")", vbTextCompare)
            If iEnd > 0 Then
                sNum = Mid(sRaw, iStart + 1, iEnd - iStart - 1)
                If Len(sNum) > 0 Then
                    If IsNumeric(sNum) Then ParenNum = CLng(sNum)
                End If
            End If
        End If
    End If
End Function

In almost every approach discussed in this tip, if the cell contains two sets of parentheses—such as "Falcon (123) Vector (456) Tango"—then the value of the first set of parentheses is returned. I said "almost every approach" because, interestingly enough, the Flash Fill approach doesn't do that. It returns whatever is in the second set of parentheses.

Note:

If you would like to know how to use the macros described on this page (or on any other page on the ExcelTips sites), I've prepared a special page that includes helpful information. Click here to open that special page in a new browser tab.

ExcelTips is your source for cost-effective Microsoft Excel training. This tip (13977) applies to Microsoft Excel 2007, 2010, 2013, 2016, 2019, 2021, 2024, and Excel in Microsoft 365.

Author Bio

Allen Wyatt

With more than 50 non-fiction books and numerous magazine articles to his credit, Allen Wyatt is an internationally recognized author. He is president of Sharon Parq Associates, a computer and publishing services company. ...

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Comments

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What is two minus 1?

2026-04-27 10:19:41

J. Woolley

The Tip says Function ParenNum2 will "accept negatives or exponents," but it fails with any numeric value that cannot be converted to a Long integer (-2,147,483,648 to 2,147,483,647). Also, it doesn't compile unless two instances of ParenNum are changed to ParenNum2, it defines but doesn't use variable J, and it ignores a multi-cell range.
Here's an alternate version that accepts real numbers including scientific notation and returns an array the same size as Target's contiguous range.

Function ParenNum3(Target As Range, Optional AsText As Boolean = False)
    Dim vArray As Variant, vFix As Variant, sRaw As String, sNum As String
    Dim iStart As Integer, iEnd As Integer, I As Integer, J As Integer
    If Target.Areas.Count > 1 Then
        vArray = CVErr(xlErrValue)
    Else
        vFix = IIf(AsText, "", 0)
        vArray = Target.Value
        If Not IsArray(vArray) Then
            ReDim vArray(1 To 1, 1 To 1)
            vArray(1, 1) = Target.Value
        End If
        For I = 1 To UBound(vArray, 1)
            For J = 1 To UBound(vArray, 2)
                sRaw = vArray(I, J)
                vArray(I, J) = ""
                iStart = InStr(1, sRaw, "(")
                If iStart > 0 Then
                    iEnd = InStr(iStart, sRaw, ")")
                    If iEnd > 0 Then
                        sNum = Mid(sRaw, iStart + 1, iEnd - iStart - 1)
                        If IsNumeric(sNum) Then vArray(I, J) = sNum + vFix
                    End If
                End If
            Next J
        Next I
    End If
    ParenNum3 = vArray
End Function

If the optional 2nd argument is TRUE, results are text; the default is FALSE for numeric values.


2026-04-25 11:29:44

J. Woolley

The Tip includes the following formula that currently requires Excel 365:
=IFNA(REGEXEXTRACT(C.:.C, "\((\d+)\)", 2), "")
If you have an older version, you can use this formula with My Excel Toolbox:
=IFNA(ForEachCell(C2:C999, "RegExMatch(@, ""\((\d+)\)"", 2)"), "")
Adjust the range C2:C999 as required. ForEachCell is described in my comment dated 2025-01-20 here: https://excelribbon.tips.net/T011725
Both formulas return text; use =IFNA(VALUE(...), "") for numeric values.
These formulas return an array aligned with the source range. To reduce the array so there are no empty results, use one of these:
=TOCOL(REGEXEXTRACT($C.:.$C, "\((\d+)\)", 2), 3)
=VALUE(TOCOL(REGEXEXTRACT($C.:.$C, "\((\d+)\)", 2), 3))
The pattern "\((\d+)\)" only returns positive integers; "\(([+-]?\d+)\)" includes negative integers; "\(([+-]?\d*\.?\d+)\)" includes numbers with a decimal point; "\(([+-]?\d*\.?\d+(?:[eE][-+]?\d+)?)\)" includes scientific notation like 7E2. The easiest way to derive a pattern is to ask Copilot or Google Gemini, which might give different answers.
See https://sites.google.com/view/MyExcelToolbox/


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