**Please Note: **
This article is written for users of the following Microsoft Excel versions: 2007, 2010, 2013, and 2016. If you are using an earlier version (Excel 2003 or earlier), *this tip may not work for you*. For a version of this tip written specifically for earlier versions of Excel, click here: Weekdays in a Month.

Ever wonder how many of a particular weekday occurs within a given month? For some people, it is important to know how many Tuesdays there are in a month. And who doesn't want to know whether a particular month will have four or five Saturdays?

Excel does not include an intrinsic function that you can use to determine the number of times a particular weekday occurs within a given month. You can, however, create your own formulas and functions to accomplish the task.

First, consider the following formula.

=4+N((WEEKDAY(DATE(YEAR($A$1),MONTH($A$1),1)))+ (DAY(DATE(YEAR($A$1),MONTH($A$1)+1,0))-28)>(7*(( WEEKDAY(DATE(YEAR($A$1),MONTH($A$1),1)))>(1+ROW()- ROW($A$2)))+(1+ROW()-ROW($A$2))))

The formula relies on a date in A1. This date should be from the month you want "tested." The formula is meant to be copied into a cell in row 2, and then copied to the six cells directly beneath that. For instance, you could copy this formula to the range of cells B2:B8. The first response (B2) is the number of Sundays in the month, the second (B3) is the number of Mondays, and so on.

The drawback to this formula is that it uses the position of the cell containing the formula as part of the formula. This means that the formula must be placed somewhere beginning in the second row.

Another drawback is that the formula is quite long and complex. If you want a shorter formula, then you need to turn to an array formula. One handy formula you can use assumes that you provide three arguments: the year (cell C2), the month (cell D2), and a weekday (cell E2). With these three items, the following formula works great:

=SUM(IF(WEEKDAY(DATE(C2, D2, ROW(INDIRECT("1:" & DAY(DATE(C2, D2+1, 0))))))=E2, 1, 0))

Remember that this is an array formula, which means that you must enter it by pressing **Shift+Ctrl+Enter**. In addition, the weekday value you enter in cell E2 must be in the range of 1 through 7, where 1 is Sunday, 2 is Monday, etc.

If your worksheet design doesn't allow for you to enter the year, month, and weekday in different cells, a clean solution is to create a user-defined function to return the count. The following macro is an example of this type of function.

Function MonthWeekDays(dDate As Date, iWeekDay As Integer) Dim dLoop As Date If iWeekDay < 1 Or iWeekDay > 7 Then MonthWeekDays = CVErr(xlErrNum) Exit Function End If MonthWeekDays = 0 dLoop = DateSerial(Year(dDate), Month(dDate), 1) Do While Month(dLoop) = Month(dDate) If WeekDay(dLoop) = iWeekDay Then _ MonthWeekDays = MonthWeekDays + 1 dLoop = dLoop + 1 Loop End Function

You use the function by entering the following in a cell:

=MonthWeekDays(A1,4)

In this usage, the first argument (cell A1) contains a date in the month being evaluated. The second argument is a numeric value representing the weekday that you want to count. This value must be in the range of 1 to 7, where 1 is Sunday, 2 is Monday, and so on.

*Note:*

If you would like to know how to use the macros described on this page (or on any other page on the *ExcelTips* sites), I've prepared a special page that includes helpful information. Click here to open that special page in a new browser tab.

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This tip (5684) applies to Microsoft Excel 2007, 2010, 2013, and 2016. You can find a version of this tip for the older menu interface of Excel here: **Weekdays in a Month**.

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2016-08-13 06:15:41

Michael (Micky) Avidan

Sorry, the previous picture was incomplete.

Here is the correct one:

(see Figure 1 below)

--------------------------

Michael (Micky) Avidan

“Microsoft® Answers" - Wiki author & Forums Moderator

“Microsoft®” MVP – Excel (2009-2017)

ISRAEL

**Figure 1.**

2016-08-13 06:12:24

Michael (Micky) Avidan

@Robert Lohman,

The use of: "1101111" has been documented within the NETWORKDAYS.INTL function since it was first launched by MS.

To my opinion the "best & easiest" way (although a little longer formula is to use the presented in the following picture.

It frees you from typing two full dates (in A1, A2).

(see Figure 1 below)

--------------------------

Michael (Micky) Avidan

“Microsoft® Answers" - Wiki author & Forums Moderator

“Microsoft®” MVP – Excel (2009-2017)

ISRAEL

**Figure 1.**

2016-08-12 20:21:48

Robert Lohman

The following formula works well:

=NETWORKDAYS.INTL(A1,A2,"1101111")

it returns 5 (No. of Wednesdays)

The"1101111" represents MTWTFSS,1 means don't count and 0 means count. Any combination may be used and even Holidays can be added in as a fourth argument.

2014-08-16 05:59:31

Michael (Micky) Avidan

=SUM(N(WEEKDAY(ROW(INDIRECT(EOMONTH(A1,-1)+1&":"&EOMONTH(A1,0))))=E2))

Michael (Micky) Avidan

“Microsoft® Answers" - Wiki author & Forums Moderator

“Microsoft®” MVP – Excel (2009-2015)

ISRAEL

2014-08-16 05:13:47

Michael (Micky) Avidan

The Array Formula can look like:

=SUM(N(WEEKDAY(DATE(C2,D2, ROW(INDIRECT("1:" &DAY(DATE(C2,D2+1, 0))))))=E2))

2) If you provide a full date in cell A1 then the formula will look like:

=SUM(N(WEEKDAY(ROW(INDIRECT(A1&":"&EOMONTH(A1,0))))=E2))

Michael (Micky) Avidan

“Microsoft® Answers" - Wiki author & Forums Moderator

“Microsoft®” MVP – Excel (2009-2015)

ISRAEL

2013-07-21 07:58:24

Willy Vanhaelen

=IF(MONTH(DATE(C2,D2,1)+35-WEEKDAY(DATE(C2,D2,1)-E2))=D2,5,4)

This formula can be adapted to the first solution:

=IF(MONTH(DATE(YEAR(A$1),MONTH(A$1),1)+35-WEEKDAY(DATE(YEAR(A$1),MONTH(A$1),1)-ROW(A1)))=MONTH(A$1),5,4)

Note that this formula can be entered anywhere in the sheet and copied down 6 rows.

This same formula can even be used in the macro:

Function MonthWeekDays(dDate As Date, iWeekDay As Integer)

If iWeekDay < 1 Or iWeekDay > 7 Then

MonthWeekDays = CVErr(xlErrNum)

Exit Function

End If

dDate = DateSerial(Year(dDate), Month(dDate), 1)

MonthWeekDays = IIf(Month(dDate + 35 - Weekday(dDate - iWeekDay)) = Month(dDate), 5, 4)

End Function

2013-07-20 06:34:36

Rik Smeesters

2013-07-20 06:26:54

Rik Smeesters

DateDiff("d";DateSerial([year];[month];1);DateSerial([year];[month]+1;1))-(DateDiff("d";DateSerial([year];[month];1);DateSerial([year];[month]+1;1))-8+Weekday(DateSerial([year];[month];1);2))7-1

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