Please Note: This article is written for users of the following Microsoft Excel versions: 2007, 2010, 2013, 2016, 2019, and Excel in Office 365. If you are using an earlier version (Excel 2003 or earlier), this tip may not work for you. For a version of this tip written specifically for earlier versions of Excel, click here: Averaging a Non-Contiguous Range.

Averaging a Non-Contiguous Range

by Allen Wyatt
(last updated October 27, 2018)

3

Tom needs to average a series of non-contiguous cells, excluding any cells that may contain zero values. Specifically, he needs to average cells A1, C1, E1, G1, and J1, but only counting those cells that don't contain zero.

Before getting into what works, let's take a look at what doesn't work. First of all, it doesn't work to simply add the cells and divide by 5; that doesn't take zero values into account. Second, it doesn't work to use COUNTIF in the denominator of your formula, as shown here:

=(A1+C1+E1+G1+J1) / COUNTIF(A1:J1,"<>0")

This doesn't work because it examines and counts cells within the entire range of A1:J1, not just the five cells you want considered in the average. You might also think that you could select your five non-contiguous cells, give them a name, and then use the name in your formula. While Excel allows you to create the name, the following gives an error:

=SUM(MyCells) / COUNTIF(MyCells,"<>0")

It appears that COUNTIF will only work with a single contiguous range, so the non-contiguous nature of the MyCells range throws the function into a tailspin. A similar problem occurs if you try to use a non-contiguous range with the AVERAGEIF function:

=AVERAGEIF(MyCells, "<>0")

Since you can't use any of the functions you might want to use, you are left to rely on a bit longer formula to calculate the average. You can calculate the average of these five cells by applying a bit of "trickery" to your denominator, in this manner:

=(A1+C1+E1+G1+J1) / ((A1<>0)+(C1<>0)+(E1<>0)+(G1<>0)+(J1<>0))

The evaluation done on each cell in the denominator returns either a 1 (for True) or a 0 (for False) depending on whether the cell contains a non-zero value or not. This series of values is added together, providing the necessary count of non-zero cells for the denominator.

Notice that the discussion here has been all about the denominator in the formula, not the numerator. The reason is simple—you can add all five values into the numerator; zero values there don't really matter. The only place they matter is in the denominator, which is what makes calculating this average so tricky.

ExcelTips is your source for cost-effective Microsoft Excel training. This tip (7845) applies to Microsoft Excel 2007, 2010, 2013, 2016, 2019, and Excel in Office 365. You can find a version of this tip for the older menu interface of Excel here: Averaging a Non-Contiguous Range.

Author Bio

Allen Wyatt

With more than 50 non-fiction books and numerous magazine articles to his credit, Allen Wyatt is an internationally recognized author. He is president of Sharon Parq Associates, a computer and publishing services company. ...

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Comments

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What is three less than 5?

2018-12-14 02:44:54

SteveJez

Marc,

Try the following;
=IFERROR((G21+J21+M21)/((G21<>0)+(J21<>0)+(M21<>0)),"Nothing to Average")


2018-12-13 15:30:58

Marc

Hi,
Thank you!!! Your suggestion above works great.
In my file I am averaging 3 cells, most of the time there is at least 1 or 2 cells with values, but occasionally all the cells are 0 and I get the following #DIV/O!. Is there away to fix this or ignoring the average calculation when all are zero..?

=(G21+J21+M21)/((G21<>0)+(J21<>0)+(M21<>0))

Really appreciate your assistance
Thank you,
Marcus

{fig}


2018-10-27 16:35:01

Eric J


This will also do the trick.

=SUM(MyCells)/(COUNT(MyCells)-FREQUENCY(MyCells,0))

Frequency will count the (0) zeros in the MyCells array and ignore blank cells and text.
Count will tally the cells in the array with numbers only.


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