Please Note: This article is written for users of the following Microsoft Excel versions: 2007, 2010, 2013, and 2016. If you are using an earlier version (Excel 2003 or earlier), this tip may not work for you. For a version of this tip written specifically for earlier versions of Excel, click here: Picking Different Random Numbers from a Range.

# Picking Different Random Numbers from a Range

by Allen Wyatt
(last updated March 26, 2016)

Let's say that you have a list of employees (or products, or widgets, or whatever) and that you want to pick two items from this list, at random. There are a couple of different worksheet functions you can use to pick items from the list, such as RANDOM and RANDBETWEEN.

Many people use the RANDBETWEEN function because it is very easy and provides a random number within a range. Thus, if you have 25 items in your list, RANDBETWEEN can return a number between 1 and 25, which can then correspond to items in the list.

For example, let's say that your list of items is in the range A2:A26, and that you give this range the name Items. You could then put the following formula in cell C2 to return a number between 1 and the number of Items:

```=RANDBETWEEN(1,ROWS(Items))
```

Copy this formula to cell C3, and you now have two random numbers that represent items from the list. In cell D2 and D3 you could put formulas like this to get the actual names from the list:

```=INDEX(Items,C2)
```

The only problem with this approach is that it is possible for both instances of RANDBETWEEN (cells C2 and C3) to return the same value, and thus you end up with the same item selected twice from your list.

One way to work around this potential problem is to actually select three items from the list instead of two. If the first two items are the same, then the third can be used as a "fallback" item to provide the unique second. The method is not foolproof, as it is possible—but quite improbable—that all three will be the same.

A different approach to selecting items from the list would be to assign each item its own random value, and then select based on the highest number in the series. The RANDOM function returns a random value between 0 and 1. In each cell of column B, just to the right of each item in column A, put this formula:

```=RAND()
```

Select the range of cells (B2:B26) and name the range, using a name such as ItemNums. You can then determine the first random name from the list by using the following array formula:

```=OFFSET(A\$1,SUM((LARGE(ItemNums,1)=(ItemNums))*ROW(ItemNums))-1,0)
```

In order to signify that this is an array formula, enter it by pressing Shift+Ctrl+Enter. The formula should return a single name. You can then use the following array formula to return the second name:

```=OFFSET(A\$1,SUM((LARGE(ItemNums,2)=(ItemNums))*ROW(ItemNums))-1,0)
```

The reason that using the RAND function approach works better than using RANDBETWEEN is because the chance that RAND will return two identical values is infinitesimally small, whereas the chances of RANDBETWEEN doing so is much higher.

ExcelTips is your source for cost-effective Microsoft Excel training. This tip (12082) applies to Microsoft Excel 2007, 2010, 2013, and 2016. You can find a version of this tip for the older menu interface of Excel here: Picking Different Random Numbers from a Range.

##### Author Bio

Allen Wyatt

With more than 50 non-fiction books and numerous magazine articles to his credit, Allen Wyatt is an internationally recognized author. He is president of Sharon Parq Associates, a computer and publishing services company. ...

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What is nine more than 3?

2016-03-28 12:53:13

Michael (Micky) Avidan

@Pieter de la Courtת
Take a look and check Marcel Beugelsdijk's suggestion.
--------------------------
Michael (Micky) Avidan
“Microsoft® Answers" - Wiki author & Forums Moderator
“Microsoft®” MVP – Excel (2009-2016)
ISRAEL

2016-03-28 06:39:03

Pieter de la Court

@Michael
You are right that this becomes very complicated for more than two random items from the list.
I don't understand your other remarks about sequential order and exceeding total items count. I see no sequence, no error. The principle of my formula is that you eliminate the risk of picking the same item twice, by skipping the first selection in the second selection process.
I look forward to your solution for larger numbers of random items.

2016-03-27 23:16:25

Marcel Beugelsdijk

Alternatively you can pick from the remaining entries with the following array formula in C2 and down:
=INDEX(\$A:\$A,SMALL(IF(ISNA(MATCH(Items,C\$1:C1,0)),ROW(Items)),RANDBETWEEN(1,COUNTA(Items)-ROWS(C\$2:C2)+1)))

2016-03-27 08:25:36

Michael (Micky) Avidan

@Pieter de la Court,
I assume that your reply/suggestion refers to a VERY Private case where only TWO Names are going to be retrieved from range A2:A26.
If not - I would be happy to see your suggested formula for retrieving 12 UNIQUE Names.
To my opinion your formula will retrieve the names in their sequential order and will fall on an Error if the indexed number will exceed the total items count.
There is, of course, a not too long formula for retrieving 12 unique items but I will present it after your reply.
--------------------------
Michael (Micky) Avidan
“Microsoft® Answers" - Wiki author & Forums Moderator
“Microsoft®” MVP – Excel (2009-2016)
ISRAEL

2016-03-26 09:28:56

Pieter de la Court

There is a more rigourous and yet simle way to avoid getting two the same rows using the Randbetween() funtion: take the second Randbetween function in of one row less, i.e formula in C3 is =Randbetween(1,Rows(Items)-1). Then use an IF function (in a separate cell, e.g. C4) to increment the result in order to skip the row already used: =IF(C3>=C2, C3+1,C3). C4 now gives the index to the second selected item, with zero probability of having the same item twice, while avoiding the calculation of a whole column of random numbers.

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