Please Note: This article is written for users of the following Microsoft Excel versions: 2007, 2010, 2013, 2016, 2019, and Excel in Microsoft 365. If you are using an earlier version (Excel 2003 or earlier), this tip may not work for you. For a version of this tip written specifically for earlier versions of Excel, click here: Finding the Address of the Lowest Value in a Range.

# Finding the Address of the Lowest Value in a Range

Written by Allen Wyatt (last updated May 17, 2022)
This tip applies to Excel 2007, 2010, 2013, 2016, 2019, and Excel in Microsoft 365

When writing a macro, you can find the lowest value in a range of cells by using the WorksheetFunction method to apply the MIN worksheet function. You may need, however, to not only find the lowest value in the range, but also the address of the first cell that contains that value.

One simple way is to simply step through the range you want to examine and derive both the lowest value and the address of the cell being examined, as in the following:

```Function FindLowestAddr(pRng As Range) As String
Dim MinVal As Double
Dim c As Range

MinVal = pRng.Cells(1).Value
For Each c in pRng
If c.Value < MinVal Then
MinVal = c.Value
End If
Next c
End Function
```

Note that this approach doesn't rely upon the MIN worksheet function at all. There is a drawback to it, however—it doesn't differentiate between cells that contain numeric values and those that don't. In other words, if the range passed to the function contains a blank cell, that cell is considered to contain a zero value, which may very well be the lowest value in the range.

One way around this is to rely upon worksheet functions from within the macro. The following macro uses both the MIN and MATCH worksheet functions to determine the location of the minimum value and then the index (offset) of that cell within the range.

```Function GetAddr(rng As Range) As String
Dim dMin As Double
Dim lIndex As Long

With Application.WorksheetFunction
dMin = .Min(rng)
lIndex = .Match(dMin, rng, 0)
End With
End Function
```

It should be noted that if you are using the macro only to discover the address because you figured there was no way to derive the desired information without the macro, then you can do away with the macro entirely by using a worksheet formula. For instance, if you want to determine the address of the lowest-valued cell in the named range MyRange, you could use the following:

```=ADDRESS(ROW(MyRange)+MATCH(MIN(MyRange),MyRange,0)-1,COLUMN(MyRange))
```

Note:

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ExcelTips is your source for cost-effective Microsoft Excel training. This tip (12744) applies to Microsoft Excel 2007, 2010, 2013, 2016, 2019, and Excel in Microsoft 365. You can find a version of this tip for the older menu interface of Excel here: Finding the Address of the Lowest Value in a Range.

##### Author Bio

Allen Wyatt

With more than 50 non-fiction books and numerous magazine articles to his credit, Allen Wyatt is an internationally recognized author. He is president of Sharon Parq Associates, a computer and publishing services company. ...

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What is one more than 7?

2022-05-17 04:27:29

Mike H

To find the address of the lowest value in a one column range why not use

2018-09-18 09:14:46

David Robinson

That last formula will only work if your range is in a single column.

I can suggest another method that doesn't involve using a macro... If you create a "helper" row and column. It will only work if the smallest value is unique however, because it doesn't do well with ties.

Below (or above) your data range, enter a formula that finds the MIN value in each column of the range, and fill this formula across. Call this HelperRow. Do the same to the right (or left) of your data range, finding the MIN in each row. Call this HelpCol. Then you can return the address by seeking the MIN value in the whole range in each helper column individually, namely

=ADDRESS(ROW(MyRange) + MATCH(MIN(MyRange), HelperCol,0)-1, COLUMN(MyRange) + MATCH(MIN(MyRange),HelperRow,0)-1)

It can't cope with ties because it finds the column with min value and row with min value and assumes the intersection of these is the lowest value, which may not be the case with multiple smallest values.

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