**Please Note: **
This article is written for users of the following Microsoft Excel versions: 2007, 2010, 2013, 2016, 2019, and Excel in Microsoft 365. If you are using an earlier version (Excel 2003 or earlier), *this tip may not work for you*. For a version of this tip written specifically for earlier versions of Excel, click here: Engineering Calculations.

Written by Allen Wyatt (last updated August 16, 2023)**This tip applies to** Excel 2007, 2010, 2013, 2016, 2019, and Excel in Microsoft 365

In an engineering environment, it is not unusual to need to "normalize" numbers in some manner. For instance, you may need to show numeric values normalized to multiples of 10^3, such that 7340 is expressed as 7.34 and 73400 is expressed as 73.4.

It is possible in Excel to use a custom number format to express information in scientific notation that will normalize the display of a number to a multiple of 10^3. To do this, you would follow these steps:

- Select the cells you want formatted.
- Display the Home tab of the ribbon.
- Click the small icon at the lower-right corner of the Number group. Excel displays the Format Cells dialog box.
- Make sure the Number tab is selected. (See Figure 1.)
- In the list of format categories, choose Custom.
- In the Type box, enter
**##0.0E+0**as your format. (This provides only one number to the right of the decimal place. If you want more, increase the number of zeros after the decimal place.) - Click on OK.

** Figure 1.** The Number tab of the Format Cells dialog box.

Now, when you enter a number such as 7340 into the cell, Excel displays it as 7.3E+3. Because of the way the cell format was entered, the portion after the E will always be a multiple of 3.

This is fine and good, but what if you want just the 7.3 in the cell, and then a metric prefix with a unit in an adjoining cell, such as kilograms? This is a bit more complex, but it can be done using formulas. For instance, let's assume you have your original number in cell A2, you wanted the normalized number in cell B2, and the metric prefix and unit name in cell C2. All you would need to do is enter the following formula in cell B2:

=IF(OR(A2>=1,A2<=-1),SIGN(A2)*(ABS(A2)/(10^(3*INT(LOG(ABS(A2))/3))))), IF(A2=0,0,SIGN(A2)*(ABS(A2)*10^(-3*INT(LOG(ABS(A2))/3)))))

Assuming the units you are working with are an imaginary unit called a foo, in cell C2 you would use a different formula, as follows:

=IF(OR(A2>=1, A2<=-1),CHOOSE(INT(LOG(ABS(A2))/3)+1, "Foos", "Kilofoos", "Megafoos", "Gigafoos", "Terafoos", "Petafoos", "Exafoos"), IF(A2=0,"",CHOOSE(INT(-LOG(ABS(A2))/3)+1, "Millifoos", "Microfoos", "Nanofoos", "Picofoos", "Femtofoos", "Attofoos")))

These formulas may seem a bit long, and they are. However, they will work for any number between approximately -9.99999E-18 to 9.99999E+20. For instance, if you put the number .000125 in cell A2, then cell B2 will contain 125 and cell C2 would contain Millifoos.

If you prefer to not use longer formulas such as these in your workbooks, you can develop a couple of VBA functions to do the trick. The following function, MySciNum, returns a normalized number. Thus, you would use =MySciNum(A2) in cell B2 to get the same results as noted above:

Function MySciNum(BaseNum As Double) As Double Select Case BaseNum Case Is >= 1 While Abs(BaseNum) > 1000 BaseNum = BaseNum / 1000 Wend Case 0 'Do nothing Case Else While Abs(BaseNum) < 1 BaseNum = BaseNum * 1000 Wend End Select MySciNum = BaseNum End Function

This function only returns a number. To return the units with the appropriate metric prefix, you would use the following function. All you need to do is pass it the cell reference and the name of a single unit. For instance, you could use =MySciPre(A2, "foo"). The macro is as follows:

Function MySciPre(BaseNum As Double, Unit As String) As String Dim OrigNum As Double Dim Pref As Integer Dim Temp As String Pref = 0 OrigNum = BaseNum Select Case BaseNum Case Is >= 1 While Abs(BaseNum) > 1000 BaseNum = BaseNum / 1000 Pref = Pref + 1 Wend Case 0 Pref = 99 Case Else While Abs(BaseNum) < 1 BaseNum = BaseNum * 1000 Pref = Pref - 1 Wend End Select Select Case Pref Case -6 Temp = "atto" & Unit Case -5 Temp = "femto" & Unit Case -4 Temp = "pico" & Unit Case -3 Temp = "nano" & Unit Case -2 Temp = "micro" & Unit Case -1 Temp = "milli" & Unit Case 0 Temp = Unit Case 1 Temp = "kilo" & Unit Case 2 Temp = "mega" & Unit Case 3 Temp = "giga" & Unit Case 4 Temp = "tera" & Unit Case 5 Temp = "peta" & Unit Case 6 Temp = "exa" & Unit Case Else Temp = "" End Select If Len(Temp) > 0 Then Temp = LCase(Temp) Temp = UCase(Left(Temp, 1)) & Mid(Temp, 2) If Abs(OrigNum) <> 1 Then Temp = Temp & "s" End If MySciPre = Temp End Function

*Note:*

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This tip (12874) applies to Microsoft Excel 2007, 2010, 2013, 2016, 2019, and Excel in Microsoft 365. You can find a version of this tip for the older menu interface of Excel here: **Engineering Calculations**.

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2023-06-12 17:54:52

dox

Since this is Engineering, shouldn't we use "a, f, p, n, µ, m, k, M, G, T, P, E" symbols?

And I, as so many others, want my engineering notation with a specific number of significant digits. Although answered in the comments, this should be included in the article.

2021-09-28 10:18:03

Jeff Slotnick

thanks for the clear direction for setting engineering notation!

2021-07-16 13:29:10

Chris Fisichella

Thank you very much!

2020-09-03 06:47:44

Yali

=C4*1000000000000&"ps"

It's a case by case basis but if all your numbers have the same unit then you can just use autofill. Hope it helps!

2019-07-29 12:08:17

Peter Atherton

When it is that important we can alway try a macro or UDF. We can't apply formatting with a function but, if you had a lot of numbers, we could write a procedure to change the format later.

Function N23Sig(ByVal ref As Range) As Double

Dim tmp As Double, L As Integer

If Len(ref) < 4 Then

N23Sig = Application.Round(ref / 1000, 2)

Exit Function

End If

tmp = ref / 1000

L = Len(tmp)

If L > 4 Then

N23Sig = Left(tmp, 4)

Else

N23Sig = tmp

End If

End Function

PS. You could write to Microsoft suggesting this option.

HTH

PPS. Actually, this formula works but I got it after writing the function. Moral; keep away from TEXT functions!

=LEFT(ROUND(I18/1000,2),4)*1

2019-07-29 01:56:37

Lars

Thanks for your effort.

I've done something similar but, as you write, it's no longer numeric.

I cannot understand why Excel does not have the option "number significant digits".

2019-07-25 11:30:52

Peter Atherton

We can use the TEXT function to get what you want but if will convert is to text and you will lose the number. See if you can live with the following:

=IF(LEN(G2)=4,TEXT(ROUND(G2/1000,2),"0.00 10^3"),(ROUND(G2/1000,(LEN(G2)-4))))

[{Fig}]

2019-07-25 11:29:38

Peter Atherton

We can use the TEXT function to get what you want but if will convert is to text and you will lose the number. See if you can live with the following:

=IF(LEN(G2)=4,TEXT(ROUND(G2/1000,2),"0.00 10^3"),(ROUND(G2/1000,(LEN(G2)-4))))

[{Fig}]

2019-07-25 03:53:57

Lars

Nice solution of 10^3.

My real question was how to get 3 significant digits without having to change number of decimals.

2019-07-24 12:05:59

Peter Atherton

Lars

Try this formula, with n in B2:

=IF(LEN(B2)=4,B2/1000,(ROUND(B2/1000,(LEN(B2)-4))))

And use this custom Format as shown:

(see Figure 1 below)

You will need to increase the decimals for the second number

**Figure 1.** Custom Format "10^3"

2019-07-24 09:32:15

MIchael Armstrong

2019-07-23 06:45:35

Lars

Got a version of Excel that uses the
ribbon interface (Excel 2007 or later)?
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