**Please Note: **
This article is written for users of the following Microsoft Excel versions: 2007, 2010, 2013, 2016, 2019, and Excel in Office 365. If you are using an earlier version (Excel 2003 or earlier), *this tip may not work for you*. For a version of this tip written specifically for earlier versions of Excel, click here: Summing Only the Largest Portion of a Range.

Christian has a range of 18 cells that contain values. He would like to find the sum of the 12 largest values in that range and wonders how to accomplish the task.

There are several ways you can approach this problem. You could, for instance, filter the values so you only have the top twelve values, and then sum those. Other approaches involve using additional columns to store intermediate values, but I'll assume that you would prefer an approach that didn't use additional columns.

To start, let's assume that your range of 18 cells is A1:A18. You can use the LARGE function to find the largest values. For instance, using this formula would find the second-largest value in the range:

=LARGE(A1:A18,2)

It is the function's second parameter that specifies which largest value, in order, you want. Thus, you could find out the sum of the 12 largest values by using a formula such as this:

=LARGE(A1:A18,1)+LARGE(A1:A18,2)+LARGE(A1:A18,3)+LARGE(A1:A18,4) +LARGE(A1:A18,5)+LARGE(A1:A18,6)+LARGE(A1:A18,7)+LARGE(A1:A18,8) +LARGE(A1:A18,9)+LARGE(A1:A18,10)+LARGE(A1:A18,11)+LARGE(A1:A18,12)

There are shorter formulas you can use to accomplish the task, however. For instance, you could simply subtract the six smallest values from the sum of the range, in this manner:

=SUM(A1:A18)-SMALL(A1:A18,1)-SMALL(A1:A18,2)-SMALL(A1:A18,3) -SMALL(A1:A18,4)-SMALL(A1:A18,5)-SMALL(A1:A18,6)

You can also, if you desire, use the SUMIF function to do a comparison of the values and sum them only if the criterion you specify is met. For instance, consider these two formulas:

=SUMIF(A1:A18,">="&LARGE(A1:A18,12)) =SUMIF(A1:A18,">"&SMALL(A1:A18,6))

The first formula will sum all the values that are greater than or equal to the twelfth largest value in the range. The second is similar in effect; it sums all the values that are greater than the sixth smallest value.

These two formulas work great if there are no duplicate values at the "boundary" established. If, however, there are more than one value that qualify as the twelfth largest or the sixth smallest, then the formulas won't return the sums you expect. In the first formula the sum will be too large (since all of the duplicate values are added to the sum) and the second formula the sum will be too small (since all of the duplicate values are excluded from the sum).

The way around this is to either go back to one of the earlier formulas (the ones that don't use SUMIF), or modify the SUMIF formula so that it takes the possibility of duplicate values into account:

=SUMIF(A1:A18,">"&LARGE(A1:A18,12))+LARGE(A1:A18,12) *(12-COUNTIF(A1:A18,">"&LARGE(A1:A18,12)))

Perhaps the best formula to get the desired result places a twist on the earlier use of the LARGE function:

=SUM(LARGE(A1:A18,{1,2,3,4,5,6,7,8,9,10,11,12}))

This formula uses an array (the part within braces), but it is not an array formula. What it does is to use the array as the second parameter of the LARGE function, thus returning all twelve largest values. These are then summed, and a single value returned.

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This tip (9422) applies to Microsoft Excel 2007, 2010, 2013, 2016, 2019, and Excel in Office 365. You can find a version of this tip for the older menu interface of Excel here: **Summing Only the Largest Portion of a Range**.

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2019-03-04 12:15:34

Dave Bonin

Let's assume cells A1:A100 contain a whole bunch of integers and that there may be duplicates.

Let's also assume that they are all between 1 and 80. This guarantees we'll have duplicates.

If we add a tiny -- but different -- amount to each value in A1:A100, then we no longer have exact duplicates.

We can use column B as a helper column. Let's put the following formula in B1:

= A1 + ROW( ) / 100000

And then copy that formula down B1:B100.

Column B now contains unique values. If cells A1:A4 contained the integers 2, 5, 2 and 15, then cells B1:B4 now contain the values 2.00001, 5.00002, 2.00003 and 15.00004.

When I sum up any batch of column B numbers, I round the values to the nearest integer, such as:

= ROUND( SUMIF( B1:B100, ">="&LARGE( B1:B100, 12 )), 0 )

As you can see, we no longer have to worry about duplicates.

If you're a little more clever (or fussy), you can use formulas like SUMPRODUCT() to eliminate the need to use a helper column.

2019-03-04 10:32:05

Daniel

ROW(INDIRECT("1:12"))

Substituting that in the array would make the formula into an array formula needing ctrl-shift-enter but there is another trick to use so that Excel can handle it using SUMPRODUCT. The resulting formula would be:

=SUMPRODUCT(LARGE(A1:A18,ROW(INDIRECT("1:12"))))

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