**Please Note: **
This article is written for users of the following Microsoft Excel versions: 2007 and 2010. If you are using an earlier version (Excel 2003 or earlier), *this tip may not work for you*. For a version of this tip written specifically for earlier versions of Excel, click here: Incrementing References by Multiples when Copying Formulas.

Tim has a worksheet in which cell B1 contains the formula =SUM(A1:A7). He wants to copy this formula down and have the range incremented by 7 rows, so that cell B2 would contain the formula =SUM(A8:A14), cell B3 would contain =SUM(A15:A21), etc. The problem is that when he copies it down, each "end" of the range is only incremented by 1 where it should be incremented by 7 to fulfill his need. He wonders how he can make Excel do the proper incrementing.

You can't make Excel do the proper incrementing using copy and paste; it just won't do it. The reason is simple—there are times when incrementing by 1 makes sense from a formulaic perspective. Since Excel can't read your mind (at least until the next version :>)), it makes the assumption that it should only increment by 1.

The solution is to change your formula. Using a couple of worksheet functions you can have Excel construct the desired range for the summation. Consider the following example of a formula that will provide the desired sum:

=SUM(INDIRECT("A" & (ROW()-1)*7+1 & ":A" & (ROW()-1)*7+7))

If you put this formula into cell B1, it works because it takes a look at the row number (returned by the ROW function) of the row in which the formula is contained. Since it is in row 1, then the formula is evaluated in this manner by Excel:

=SUM(INDIRECT("A" & (ROW()-1)*7+1 & ":A" & (ROW()-1)*7+7)) =SUM(INDIRECT("A" & (1-1)*7+1 & ":A" & (1-1)*7+7)) =SUM(INDIRECT("A" & 0*7+1 & ":A" & 0*7+7)) =SUM(INDIRECT("A" & 0+1 & ":A" & 0+7)) =SUM(INDIRECT("A" & 1 & ":A" & 7)) =SUM(INDIRECT("A1:A7")) =SUM(A1:A7)

What you end up with in B1 is the sum you desired. (The INDIRECT function uses the value in the string as if it was a real range, which is what you want.) When you copy the formula down the column, as the row number increments the formula provides the proper increments of 7 on both ends of the range.

There are other variations on this technique that you can use. The only difference is that the variations use different worksheet functions to accomplish the same task. For instance, the following variation still uses the ROW function, but then ultimately relies on the OFFSET function to calculate the desired range:

=SUM(OFFSET(A1,((ROW()-1)*6),0):OFFSET(A7,((ROW()-1)*6),0))

A shorter approach that uses OFFSET is as follows:

=SUM(OFFSET($A$1,ROW()*7-7,0,7,1))

Regardless of the approach, you can probably tell that the idea is to come up with a formula that uses the row in which the formula appears in order to construct the range that you really want. Each of the examples so far assumes that you are starting in cell B1. If you want to start in cell B2, then you'll need to modify the formulas to account for whatever row you are starting on. To give you just an idea of how this works, if you were starting in cell B2, instead, the three formulas presented in this tip would be modified in the following ways:

=SUM(INDIRECT("A" & (ROW()-2)*7+2 & ":A" & (ROW()-2)*7+8)) =SUM(OFFSET(A2,((ROW()-2)*6),0):OFFSET(A8,((ROW()-2)*6),0)) =SUM(OFFSET($A$2,(ROW()-1)*7-7,0,7,1))

Start at a different location, and you'll need to make further modifications to the formula you choose to use.

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This tip (8387) applies to Microsoft Excel 2007 and 2010. You can find a version of this tip for the older menu interface of Excel here: **Incrementing References by Multiples when Copying Formulas**.

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2017-09-01 03:10:39

marjattanb

formula in Cell K11 would be: =SUM(E10:K10), select area E11:K11 and copy and paste to the right again as far as you need. It works.

You can make the formula on the data page and cut it and paste onto the second page, where you actually need the formula. Make sure that where you paste it has those 6 columns to the left of it:

e.g. =SUM(Sheet1!E10:K10) into cell G4 on Sheet2 (supposing you have 3 rows of title-area on top). Then select area A4:G4 and copy it onto right as far as you need.

Finally select row 4, Find Value, leave Find field empty, find all, select all (CTRL A) and delete all.

I believe it works.

2017-08-31 03:05:19

Marjatta N-B

I use to do this by writing the wanted formula "=SUM(A1:A7)" into B7, then selecting the area B1:B7 and Copy/Paste down as far as necessary. The only trick is that the number of rows where you paste the 7-row copied area also must be divisible by 7.

Secondly I choose Col B, Find all empty cells (Find What - field is left empty), Select all (CTRL A), and Delete Cells/ Shift Cells Up.

2017-08-30 10:50:00

Frank

2015-09-17 12:46:55

Kate

2015-08-20 04:21:49

Lau Hestbek

In your example [ =SUM(OFFSET($A$1,ROW()*7-7,0,7,1)) ] this means that you can write it as:

=SUM(OFFSET($A$1,ROW(1:1)*7-7,0,7,1))

Or

=SUM(OFFSET($A$1,ROW(A1)*7-7,0,7,1))

A huge problem with this (and your) approach though is that the formula changes if you insert a new row on top. Also as Bryan points out, the OFFSET- and INDIRECT-functions are volatile.

2013-12-02 11:20:39

Bryan

However, taking the question at face value, there is another way to do it that doesn't use the volatile INDIRECT or OFFSET functions. The INDEX function also provides a reference to another cell, but is not volatile. Knowing that, you can use the following equation:

=SUM(INDEX(A:A,(ROW()-1)*7+1):INDEX(A:A,ROW()*7))

So to do the analysis like Allen did for row 1:

=SUM(INDEX(A:A,(ROW()-1)*7+1):INDEX(A:A,ROW()*7))

=SUM(INDEX(A:A,(1-1)*7+1):INDEX(A:A,1*7))

=SUM(INDEX(A:A,1):INDEX(A:A,7))

=SUM(A1:A7)

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