Please Note: This article is written for users of the following Microsoft Excel versions: 2007, 2010, 2013, 2016, 2019, Excel in Microsoft 365, and 2021. If you are using an earlier version (Excel 2003 or earlier), this tip may not work for you. For a version of this tip written specifically for earlier versions of Excel, click here: Pulling Initial Letters from a String.

# Pulling Initial Letters from a String

Written by Allen Wyatt (last updated November 11, 2023)
This tip applies to Excel 2007, 2010, 2013, 2016, 2019, Excel in Microsoft 365, and 2021

Rajeev needs a formula that will extract the first letters of a series of words. For instance, if a cell contains the text "Rajeev Kumar Pandey" he would like to extract, into another cell, the letters "RKP". The number of words in series can vary from cell to cell.

There are a couple of ways that this task can be approached. It is assumed, to begin with, that you don't want to modify the structure of your worksheet by adding intermediate columns. This assumption precludes, as well, the use of the Text to Columns feature to split the original string into individual words.

The key to the problem is making sure that your formula can determine where the spaces are in the original string. You might think that a formula such as the following will do the job:

```=LEFT(A1,1)&MID(A1,FIND(" ",A1,1)+1,1)&MID(A1,FIND(" ",A1,FIND(" ",A1,1)+1)+1,1)
```

This formula works partially. It works just fine if the original string has two spaces separating three words. If there are any fewer words then the formula returns an error. If there are any more words, then it returns only the first letters of the first three words (it ignores anything after the third word).

This means that the formula needs to not only check for spaces, but handle errors if there are no spaces or if there are too few spaces. The error checking means that the formula unavoidably becomes longer:

```=IFERROR(LEFT(A1,1),"")&IFERROR(MID(A1,FIND(" ",A1)+1,1),"")&
IFERROR(MID(A1,FIND(" ",A1,FIND(" ",A1)+1)+1,1),"")&
IFERROR(MID(A1,FIND(" ",A1,FIND(" ",A1,FIND(" ",A1)+1)+1)+1,1),"")&
IFERROR(MID(A1,FIND(" ",A1,FIND(" ",A1,FIND(" ",A1,FIND(" ",A1)+1)+1)+1)+1,1),"")
```

Remember that this is a single formula, even though it is shown here on multiple lines. This formula will handle, properly, anything from 0 to 5 words in a string. It also assumes that the string doesn't start or end with a space and that it doesn't contain multiple numbers of spaces between words. If you want to handle a larger number of words or other potential complications (such as the number of spaces between words), then it is best to use a user-defined function.

There are any number of ways that a user-defined function could pull the leading characters from the words of a string. The following is one rather simple example:

```Function Initials(Raw As String) As String
Dim Temp As Variant
Dim J As Integer

Temp = Split(Trim(Raw))
For J = 0 To UBound(Temp)
Initials = Initials & Left(Temp(J), 1)
Next J
End Function
```

The Split function "tears apart" a string based on where spaces occur within it. The individual words in the string are placed into an array (in this case, Temp) where you can then access individual words. To use the function in your worksheet, simply use something like this:

```=Initials(A1)
```

Note:

If you would like to know how to use the macros described on this page (or on any other page on the ExcelTips sites), I've prepared a special page that includes helpful information. Click here to open that special page in a new browser tab.

ExcelTips is your source for cost-effective Microsoft Excel training. This tip (8663) applies to Microsoft Excel 2007, 2010, 2013, 2016, 2019, Excel in Microsoft 365, and 2021. You can find a version of this tip for the older menu interface of Excel here: Pulling Initial Letters from a String.

##### Author Bio

Allen Wyatt

With more than 50 non-fiction books and numerous magazine articles to his credit, Allen Wyatt is an internationally recognized author. He is president of Sharon Parq Associates, a computer and publishing services company. ...

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What is eight minus 0?

2023-11-25 15:33:32

J. Woolley

Re. the JoinAsText function in my most recent comment below, there was an error associated with recursion. Please locate the following statement
text = text & JoinAsText(Delimiter, IgnoreEmpty, item) & Delimiter
and replace it with these statements
Dim temp As String
temp = JoinAsText(Delimiter, IgnoreEmpty, item)
If Not (IgnoreEmpty And temp = "") Then text = text & temp & Delimiter
This has been corrected in My Excel Toolbox.

2023-11-17 18:07:31

J. Woolley

My Excel Toolbox now includes the following function to combine values, arrays, and/or cell ranges into a delimited text string:
=JoinAsText(Delimiter,IgnoreEmpty,Values,...)
This function matches Excel 2019's TEXTJOIN; see https://support.microsoft.com/en-us/office/textjoin-function-357b449a-ec91-49d0-80c3-0e8fc845691c
If Delimiter is a null string (""), the result is the same as CONCAT.
Here is an abbreviated version:

Function JoinAsText(Delimiter As String, IgnoreEmpty As Boolean, _
ParamArray Values() As Variant) As String
Dim valu As Variant, item As Variant, text As String
For Each valu In Values
If IsArray(valu) Then
For Each item In valu
text = text & JoinAsText(Delimiter, IgnoreEmpty, item) _
& Delimiter
Next item
ElseIf IsError(valu) Then
text = text & CStr(valu) & Delimiter
ElseIf Not (IgnoreEmpty And valu = "") Then
text = text & valu & Delimiter
End If
Next valu
If text <> "" Then JoinAsText = Left(text, (Len(text) - Len(Delimiter)))
End Function

Notice this function is recursive.

2023-11-15 06:36:19

Mike J

An alternative solution for users of earlier versions of Excel (tested using Excel2010) is to download UDFs for CONCAT and TEXTJOIN.
They work perfectly with J.Woolley's SplitText function.
Use Ctrl+Shift+Enter to convert to array formula.

UDF for CONCAT() is available here:

UDF for TEXTJOIN() is available here:

I'm unsure about TEXTJOIN, but if using SplitText, the Trim() function does not seem to be required.

2023-11-14 11:44:39

J. Woolley

Re. my most recent comment below, if your version of Excel does not include TEXTJOIN or CONCAT here is a clever trick that permits use of CONCATENATE instead (with manual intervention). To get initials from a name in cell A1:
1. Enter the following formula in cell B1 (for example):
=LEFT(SplitText(TRIM(A1)," "),1)
2. Select cell B1 and press F2 then Ctrl+A then F9 then Enter.
3. Select cell B1 and press F2 again, then edit the formula to replace curly brackets { } with parentheses ( ) and add CONCATENATE after the equal sign, then press Enter.
For example, if cell A1 contains the following text
Rajeev    Kumar Pandey
after step 2 cell B1 should contain the array constant formula
={"R","K","P"}
and step 3 should convert that to the formula
=CONCATENATE("R","K","P")
which returns the value
RKP
See https://trumpexcel.com/concatenate-excel-ranges/

2023-11-12 11:10:19

J. Woolley

As noted by Allen, Alex Blakenburg's excellent formula currently requires Excel 365 because it uses TEXTSPLIT. If you don't have Excel 365, My Excel Toolbox includes the SplitText function described in my earlier comment here: https://excelribbon.tips.net/T013906_Splitting_Cells_to_Individual_Columns.html
Using SplitText, Alex's formula can be changed to
=TEXTJOIN("",TRUE,LEFT(SplitText(A1," "),1))
or with TRIM as discussed in my previous comment below
=TEXTJOIN("",TRUE,LEFT(SplitText(TRIM(A1)," "),1))
This formula can be simplified by using CONCAT instead of TEXTJOIN:
=CONCAT(LEFT(SplitText(TRIM(A1)," "),1))
I believe TEXTJOIN and CONCAT both require Excel 2019 or later.

2023-11-12 10:47:56

J. Woolley

The last formula in my previous comment below had an error. It should have been
=TEXTJOIN("",TRUE,LEFT(TEXTSPLIT(TRIM(A1)," "),1))

2023-11-11 11:36:23

J. Woolley

Re. the Tip's Initials function, it should be noted that VBA's Trim function does not work the same as Excel's TRIM function. Excel's TRIM removes all spaces from text except for single spaces between words. VBA's Trim only removes leading and trailing spaces. Therefore, if Raw has 2 words separated by 2 spaces, the following statement
Temp = Split(Trim(Raw))
will return 3 substrings, not 2. However, the 2nd substring is null (zero-length), so the macro doesn't care because
Left(Temp(J), 1)
returns the null string for this case.
This issue can be avoided by replacing the first statement above with
Temp = Split(WorksheetFunction.Trim(Raw))
For the same reasons, Alex Blakenburg's function could be changed to
=TEXTJOIN("",TRUE,LEFT(TEXTSPLIT(TRIM(A1," "),1))
but it matters less because the 2nd argument of TEXTJOIN is TRUE (ignore empty).

2023-11-11 08:47:26

Allen

Awesome formula, Alex, for those using the version of Excel with Microsoft 365.

2023-11-11 08:27:46

Alex Blakenburg

This will produce the same result as the Macro Function Initials
=TEXTJOIN("",TRUE,LEFT(TEXTSPLIT(A1," "),1))

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