**Please Note: **
This article is written for users of the following Microsoft Excel versions: 2007, 2010, 2013, 2016, 2019, and Excel in Office 365. If you are using an earlier version (Excel 2003 or earlier), *this tip may not work for you*. For a version of this tip written specifically for earlier versions of Excel, click here: Working In Feet and Inches.

If you work in one of the construction trades, you may wonder if there is a way to have Excel work in feet and inches. The answer, of course, is yes and no. (How's that for specific?)

Let's look at the "no" answer first. If you are looking for a way to make Excel do things like math using feet and inches, there is no native ability to do that. In other words, you can't tell Excel to consider a column as "feet and inches" and then have it automatically add a set of cells containing lineal feet. A quick search of the Internet reveals that there are a number of Excel add-ins that you can find—some for free—that will do real math for feet and inches. These, of course, would require learning exactly how to use them to achieve what you want. The following site was among those suggested by different *ExcelTips* subscribers. (Even though the information on the page is older, it is still applicable to current versions of Excel.)

http://lacher.com/examples/lacher18.htm

Now for the "yes" portion of the answer. You can, of course, use separate columns for feet and inches. In this way it is relatively easy to add the values in the columns—one would simply be the sum of feet, and the other the sum of inches. Since the sum of the inches would most likely exceed 12, you could, in a different cell, adjust the finished feet and inches as necessary.

Another approach is to simply work in inches, which is the lowest common denominator. For instance, if you had a length of 5 feet 6 inches, you would put the value 66 in a cell. You could then do any number of math functions on these values. In another cell you could use a formula, such as the following, to display an inches-only value as feet and inches:

=INT(A1/12) & " ft. " & MOD(A1,12) & " in."

*ExcelTips* is your source for cost-effective Microsoft Excel training.
This tip (10612) applies to Microsoft Excel 2007, 2010, 2013, 2016, 2019, and Excel in Office 365. You can find a version of this tip for the older menu interface of Excel here: **Working In Feet and Inches**.

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2016-02-05 14:21:48

Josh

Correction:

=ROUNDDOWN(DOLLARFR(C14/12,12),0)&"ft "&ROUND(MOD(DOLLARFR(C14/12,12),1),2)*100&"in"

2016-02-05 14:20:14

Josh

=ROUNDUP(DOLLARFR(C14/12,12),0)&"ft "&ROUND(MOD(DOLLARFR(C14/12,12),1),2)*100&"in"

Where C14 contains the value you are looking to convert

2015-01-28 05:44:39

Michael (Micky) Avidan

I do hope that no Canadian driver still uses the "imperial" (left) side of the road. :)

Michael (Micky) Avidan

“Microsoft® Answers" - Wiki author & Forums Moderator

“Microsoft®” MVP – Excel (2009-2015)

ISRAEL

2015-01-27 18:53:16

Aldo

I live in Canada. We use metric as well. But there are still many projects using imperial measurements, and our building code references both systems of measurements.

2015-01-27 05:27:10

Willy Vanhaelen

Whow, am I happy I live in a country where only metric measurements are used :-)

2015-01-26 17:55:08

Public Function FeetInch(Inch As Double, Optional Denominator As Integer = 16) As String

Dim Negative As Boolean

Dim FeetValue As Long

Dim InchValue As Long

Dim FractionValue As Double

Dim FractionReductionCount As Integer

Dim Numerator As Integer

Dim F As String, i As String, Fr As String

Negative = (Inch < 0)

If Negative Then Inch = Inch * -1

FeetValue = Int(Inch / 12)

InchValue = Int(Inch - FeetValue * 12)

FractionValue = Round((Inch - FeetValue * 12 - InchValue) * Denominator, 0) / Denominator

If FractionValue = 1 Then

FractionValue = 0

InchValue = InchValue + 1

End If

FractionReductionCount = 0

Numerator = FractionValue * Denominator

If FractionValue <> 0 Then

Do Until Int(Numerator / 2) <> Numerator / 2

Numerator = Numerator / 2

FractionReductionCount = FractionReductionCount + 1

Loop

End If

F = FeetValue & "'-"

If FeetValue = 0 Then F = ""

Fr = Numerator & "/" & Denominator / 2 ^ FractionReductionCount & """"

If FractionValue = 0 Then Fr = """"

i = InchValue & " "

If InchValue = 0 And FeetValue = 0 Then i = ""

If FractionValue = 0 Then i = Trim(InchValue)

FeetInch = IIf(Negative, "-", "") & F & i & Fr

End Function

Public Function Inch(ByVal FeetInch As String, Optional Rounding As Integer = 0) As Double

Dim Negative As Boolean

Dim Apos As Long 'Apostrophe

Dim Hpos As Long 'Hyphen

Dim Spos As Long 'Space

Dim Dpos As Long 'Divider

Dim Qpos As Long 'Quotation

Dim EndValue As Double

Dim FeetValue As Double

Dim InchValue As Double

Dim Numerator As Double

Dim Denominator As Double

If Left(FeetInch, 1) = "*" Then

FeetInch = [AddLongLength] & Right(FeetInch, Len(FeetInch) - 1)

End If

FeetValue = 0

InchValue = 0

Numerator = 0

Denominator = 1

If Left(FeetInch, 1) = "-" Then

Negative = (Left(FeetInch, 1) = "-")

FeetInch = Right(FeetInch, Len(FeetInch) - 1)

End If

Qpos = InStr(FeetInch, """") 'Quotation

If Qpos > 0 Then FeetInch = Left(FeetInch, Qpos - 1)

Dpos = InStr(FeetInch, "/") 'Divider

Spos = InStr(FeetInch, " ") 'Space

Hpos = InStr(FeetInch, "-") 'Hyphen

Apos = InStr(FeetInch, "'") 'Apostrophe

If Dpos > 0 Then 'Divider indicates fraction in string

Select Case True

Case Spos > 0 'Space

Numerator = CDbl(Mid(FeetInch, Spos + 1, Dpos - Spos - 1))

Denominator = CDbl(Mid(FeetInch, Dpos + 1))

FeetInch = Left(FeetInch, Spos - 1)

Case Hpos > 0 'Hyphen

Numerator = CDbl(Mid(FeetInch, Hpos + 1, Dpos - Hpos - 1))

Denominator = CDbl(Mid(FeetInch, Dpos + 1))

FeetInch = Left(FeetInch, Hpos - 1)

Case Apos > 0 'Apostrophe

Numerator = CDbl(Mid(FeetInch, Apos + 1, Dpos - Apos - 1))

Denominator = CDbl(Mid(FeetInch, Dpos + 1))

Case Else 'Fraction Only

Numerator = CDbl(Left(FeetInch, Dpos - 1))

Denominator = CDbl(Right(FeetInch, Len(FeetInch) - Dpos))

FeetInch = ""

End Select

End If

Hpos = InStr(FeetInch, "-") 'Hyphen

If Hpos > 0 Then

If Len(FeetInch) > Hpos Then

InchValue = CDbl(Right(FeetInch, Len(FeetInch) - Hpos))

FeetInch = Left(FeetInch, Hpos - 1)

End If

End If

Apos = InStr(FeetInch, "'") 'Apostrophe

If Apos > 0 Then

FeetValue = CDbl(Left(FeetInch, Apos - 1))

FeetInch = Right(FeetInch, Len(FeetInch) - Apos)

End If

If Len(FeetInch) > 0 Then InchValue = InchValue + CDbl(FeetInch)

If Rounding = 0 Then

EndValue = FeetValue * 12 + InchValue + Numerator / Denominator

Else

EndValue = Round((FeetValue * 12 + InchValue + Numerator / Denominator) * Rounding, 0) / Rounding

End If

If Negative Then

EndValue = EndValue * -1

End If

Inch = EndValue

End Function

If any of you streamline code, let me know please. Thanks.

2015-01-26 09:34:05

Glenn Case

=DOLLARFR(66/12,12)

will produce 5.06, that's likely what MarcelBeug was referring to.

Like Erik, I had never heard of these functions, but this is an interesting use of them.

2015-01-25 07:12:06

Michael (Micky) Avidan

I looked at your ALTERNATIVE suggestion but with all due respect I could not understand how it could be for any help in converting 66 Inches into Feet and Inches - which, to the best of my understanding, was the main goal of this tip.

I hope you understand that my comment comes, mainly, due to the use of the word: ALTERNATIVELY.

Michael (Micky) Avidan

“Microsoft® Answers" - Wiki author & Forums Moderator

“Microsoft®” MVP – Excel (2009-2015)

ISRAEL

2015-01-24 11:12:15

Erik

2015-01-24 05:56:56

MarcelBeug

DOLLARDE works the other way around, so DOLLARDE(5.06, 12) results in 5.5.

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